(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A loaded penguin sled weighing 66 N rests on a plane inclined at angle θ = 18° to the horizontal (Fig. 6-23). Between the sled and the plane, the coefficient of static friction is 0.27, and the coefficient of kinetic friction is 0.18. (a) What is the minimum magnitude of the force , parallel to the plane, that will prevent the sled from slipping down the plane? (b) What is the minimum magnitude F that will start the sled moving up the plane? (c) What value of F is required to move the sled up the plane at constant velocity?

2. Relevant equations

Fk=uFn

Fsmax=uFn

3. The attempt at a solution

a) I know the acceleration of the sled would be negative but if I set it up like

Fa-Fs=-ma... it can't be solved

b) Fsmax=uFn

=.27(6.73)(9.8)

=17.81

c)Fa-Fk=ma

Fa-Fk=0

Fa=Fk

Fa=uFn

=11.87N

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# Homework Help: Sled on a hill with friction

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