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Homework Help: Slide loving pig force

  1. Oct 3, 2004 #1
    slide loving pig force....

    ok, heres a problem that is supposed to be easy, and i thought i knew how to do it, but obviously not, cause i cant get the right answer....

    In figure 6-21, a slide loving pig slides down a certain 24° slide in twice the time it would take to slide down a frictionless 24° slide. What is the coefficient of kinetic friction between the pig and the slide?

    what i did:
    i set 2 times the force without friction (mgsin24) equal to the force without friction minus friction (mgsin24-MUkmgcos24) and tried to solve for MUk...... but that didnt work, and i have no idea what happened. heres what the equation i used looked like:
    2(mgsin24)=mgsin24-MUkmgcos24.... so that is the same as
    then sin24=-MUkcos24
    so tan24=-MUk
    buuuut that didnt work, so what do i do wrong?
  2. jcsd
  3. Oct 3, 2004 #2
    Two times the time doesn't translate to two times the force IIRC
  4. Oct 3, 2004 #3
    whats a way to relate the force to time? i cant find a formula to do that?
  5. Oct 3, 2004 #4
    this problem is supposed to be a 1 of 3 dot problem (How hard it is, 3 is hardest) so why is it so hard for me?
  6. Oct 3, 2004 #5
    This doesn't really follow up with what I just said though but the resultant force of the slide with friction is less than the no-friction slide (and wouldn't go UP by any factor > 1) To figure the factor by which the resultant force is different from the no-friction force consider the units of force and how time plays into it.
    Last edited by a moderator: Oct 3, 2004
  7. Oct 3, 2004 #6
    uhhhh in lamen's terms? i cant figure out what you're saying
  8. Oct 3, 2004 #7
    Here's what your equation above said to me when you said 2 * mgsin(24) = mgsin(24)-mg(cos(24))*u or whatever:

    Twice the force of mgsin(24) is created by applying friction to the same force which of course doesn't make sense.

    F = kg*m/s^2 right? What effect does making s 2s have?
  9. Oct 3, 2004 #8
    so your saying make it 1/2 mgsin(24) yadda yadda yadda?
  10. Oct 3, 2004 #9
    not quite.. Take a close look at the relationship of force to time given its units above.
  11. Oct 3, 2004 #10
    ohhhhh 1/4? that seems to make sense, so if i made it 1/4 (instead of 2), then did the rest teh same way i did it, it shoudl work?
  12. Oct 3, 2004 #11
    I'm fairly sure it would. You won't know for certain until you try it out I guess. I'm not exactly a physics expert just happened to see something possibly wrong.
  13. Oct 3, 2004 #12
    heck yeah man, that worked.... thanks a lot! now how bout my other thread, any ideas there?
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