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ok, heres a problem that is supposed to be easy, and i thought i knew how to do it, but obviously not, cause i cant get the right answer....

In figure 6-21, a slide loving pig slides down a certain 24° slide in twice the time it would take to slide down a frictionless 24° slide. What is the coefficient of kinetic friction between the pig and the slide?

what i did:

i set 2 times the force without friction (mgsin24) equal to the force without friction minus friction (mgsin24-MUkmgcos24) and tried to solve for MUk...... but that didnt work, and i have no idea what happened. heres what the equation i used looked like:

2(mgsin24)=mgsin24-MUkmgcos24.... so that is the same as

2sin24=sin24-MUkcos24

then sin24=-MUkcos24

so tan24=-MUk

buuuut that didnt work, so what do i do wrong?

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# Homework Help: Slide loving pig force

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