Sliding Box

  • Thread starter TG3
  • Start date
  • #1
TG3
66
0

Homework Statement


A box of unknown mass slides across a frictionless floor with an initial speed of 4.7 m/s. It encounters a rough region where the coefficient of friction is µk = 0.3
Part 1:
What is the shortest length of rough floor which will stop the box?
Part 2:
What is the shortest length of rough floor which will stop the box?

Homework Equations



vf^2 = vi^2 + 2a delta x.
Frictional force = mew times the normal force

The Attempt at a Solution


Final velocity = 0, so
0 = 4.7 ^2 + 2A delta x.
A = the frictional force.
How can I determine the normal force (and after that, the frictional force, and after that, the change in distance) if I don't know the weight of the box? Is there another way to do this problem?
 

Answers and Replies

  • #2
LowlyPion
Homework Helper
3,115
6
F = ma = μ*m*g

a = μ*g

Does that help?
 
  • #3
TG3
66
0
Yes- it certainly does. With that I was able to solve both parts of the problem. I'm writing that formula down for future reference...
 
  • #4
LowlyPion
Homework Helper
3,115
6
Yes- it certainly does. With that I was able to solve both parts of the problem. I'm writing that formula down for future reference...

Better to understand it and remember it forever.
 

Suggested for: Sliding Box

Replies
20
Views
173
  • Last Post
Replies
16
Views
442
  • Last Post
Replies
27
Views
718
Replies
20
Views
470
Replies
4
Views
300
Replies
15
Views
498
Replies
23
Views
128
  • Last Post
Replies
8
Views
814
Replies
7
Views
425
Top