How do you get from equation (2) to (3) in quantum mechanics?

  • Thread starter resurgance2001
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In summary, the conversation is about the uncertainty principle in quantum mechanics and how it can be derived from the Schwarz inequality. The speaker is struggling to understand the author's explanation of the derivation, specifically how they go from equation (2) to (3). Another author's version of the equation is slightly different, but they also do not provide an explanation. The issue is resolved when it is pointed out that the expectation value of the product of a constant and an operator is equal to the constant multiplied by the expectation value of the operator.
  • #1
resurgance2001
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I am reading a book about quantum mechanics and the author is trying to show how the uncertainty principle can be obtained from the Schwarz inequality.

Without going into the whole thing there is one point I get stuck following what he is doing.We have an operator called DA.

We start with DA = A - <A> (1)

From this we get:

<DA^2> = <A^2 + <A>^2 - 2A<A>> (2)

I can just about live with that. But then says: taking the expectation value of the last term in this equation, you get this result:

<DA^2> = <A^2> - <A>^2 (3)I just can't see how he goes from (2) to (3). I have checked and found the same thing written by another author. That author's version of (2) is slightly different, but only in the way he puts various bracket round things and then he too jumps to the same conclusion giving no explanation of how it was done.

Can anyone help? Thanks Pete
 
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  • #2
Note that ##\langle A \rangle## is a (real) number. Thus ##\langle \langle A \rangle A \rangle=\langle A \rangle\langle A \rangle=\langle A \rangle^2.##
 
  • #3
Great - got it! Thanks
 

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