Fnet = ma Ff = -0.3375/0.08 = -4.219N

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In summary, the problem involves shooting a 0.08 kg box with a 60 N/m slingshot stretched back 0.15m. The box slides 4.22m before coming to a stop. To calculate the force of friction acting on the box, the equation EPE = 1/2kx^2 is used and the work done by the slingshot is opposed by the work done by the frictional force. The work done by the friction force F is calculated using the equation W = F*D, and the result is approximately -0.08 N. This value represents the Force of Friction.
  • #1
CollegeJunior
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Homework Statement



You shoot a 0.08 kg box across the ground with 60 N/m slingshot, stretched back 0.15m. The box slides 4.22m before coming to a stop. What is the force of friction acting on the box as it slides across the ground?

Homework Equations



EPE = 1/2kx^2

The Attempt at a Solution



E1 = 1/2(60)(0.15)^2
E1 = 0.3375J
W = 0 - 0.3375J = -0.3375J
 
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  • #2
CollegeJunior said:

The Attempt at a Solution



E1 = 1/2(60)(0.15)^2
E1 = 0.3375J
W = 0 - 0.3375J = -0.3375J

Right so all the work done by the slingshot will be opposided by the work done by the frictional force.

How would you calculate the work done by the friction force F with a distance of 4.22 m ?
 
  • #3
rock.freak667 said:
Right so all the work done by the slingshot will be opposided by the work done by the frictional force.

How would you calculate the work done by the friction force F with a distance of 4.22 m ?

W = F * D, so F = W / D? I got around -0.08 N for force. Is that the Force of Friction?
 
  • #4
CollegeJunior said:
E1 = 1/2(60)(0.15)^2
E1 = 0.3375J
You seem to have halved twice over.
 
  • #5
haruspex said:
You seem to have halved twice over.

?
 
  • #6
CollegeJunior said:
?

Verify your calculation of E1.
 

1. What does "Fnet = ma Ff = -0.3375/0.08 = -4.219N" mean?

"Fnet = ma Ff = -0.3375/0.08 = -4.219N" is an equation that represents Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this specific equation, "Fnet" represents the net force, "m" represents the mass of the object, "a" represents the acceleration, and "Ff" represents the force of friction. The value of -4.219N represents the net force in Newtons.

2. What is the significance of the negative sign in "-0.3375/0.08 = -4.219N"?

The negative sign in this equation represents the direction of the force. In this case, it is indicating that the force is acting in the opposite direction of the object's motion. In other words, the force is opposing the motion of the object.

3. How is the value of "Ff" calculated in the equation "Fnet = ma Ff = -0.3375/0.08 = -4.219N"?

The value of "Ff" is calculated by multiplying the coefficient of friction, which is -0.3375 in this case, by the normal force. The normal force is the force exerted by the surface on which the object is resting. In this equation, the normal force is divided by the mass of the object (0.08) to find the value of "Ff".

4. Can the equation "Fnet = ma Ff = -0.3375/0.08 = -4.219N" be used for any object?

Yes, the equation "Fnet = ma Ff = -0.3375/0.08 = -4.219N" can be used for any object, as long as the mass and acceleration are known. However, the value of the coefficient of friction may vary depending on the surface and the object's material.

5. How is the equation "Fnet = ma Ff = -0.3375/0.08 = -4.219N" used in real-life situations?

The equation "Fnet = ma Ff = -0.3375/0.08 = -4.219N" is commonly used in physics and engineering to calculate the net force and acceleration of an object. It can be used to design structures, analyze the motion of objects, and determine the forces acting on an object. It is also used in everyday situations such as driving a car, where the force of friction between the tires and the road affects the acceleration of the vehicle.

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