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Slipping in moving belt

  1. Feb 15, 2004 #1
    I have no clue how to start solving the question as follows:
    A box is dropped onto a conveyor belt moving at 1.7 m/s. If the coefficient of friction between the box adn the belt is 0.7, what distance doest the box move before it moves without slipping? (g = 9.8 m/s)

    What is the horizontal force to move the box on the belt?

    Thanks alot.
     
  2. jcsd
  3. Feb 15, 2004 #2
    Friction.
     
  4. Feb 15, 2004 #3
    Why it stop slipping? How should I start my formula? Thanks
     
  5. Feb 15, 2004 #4
    What does an object do when a force acts on it?
     
  6. Feb 15, 2004 #5
    acceleration

    It should create acceleration. Now, I have just tried to solve it and the following is the formula I used.

    mg(0.7) = ma, a = 6.86. I assumed this was the acceleration responsible for moving box. Then, I use V = Vo - at
    0 = 1.7 - 6.86t, t = 0.2478, substituted into d = Vot - 0.5 a t^2,
    d= 1.7t - 0.5 * 6.86 * (0.2478)^2
    = 0.2106 m
    Is there anything (step) I missed or made mistake?

    Thanks alot
     
  7. Feb 15, 2004 #6
    Looks OK to me.

    Although I would have written
    vf = v0 + at
    and let v0=0 and vf=1.7 m/s

    Then d = 0 + .5at2

    Gives the same answer.
     
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