I know that the standard definition for a slope field is ##\frac{dy}{dx} = f(x, y)##, but and if the equation given is a second-order ODE ##a\frac{d^2y}{dx^2}+b\frac{dy}{dx}+cy=0## or a system of first-order ODEs ##A\frac{d\vec{r}}{dt}+\vec{b}=\vec{0}##, the definition for slope field continues the same? I need only isolate dy/dx and thus the slope field is automatically generated?(adsbygoogle = window.adsbygoogle || []).push({});

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# Slope fields

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