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Slope of Tangent Line-Theta

  1. Aug 4, 2013 #1
    1. The problem statement, all variables and given/known data
    Calculate a function of theta that gives the slope of the tangent line (dy/dx) to the polar curve r at some angle theta.


    2. Relevant equations
    dy/dx= f'(theta)sin(theta) + f(theta)cos(theta)/[f'(theta)cos(theta) - f(theta) sin(theta)]


    3. The attempt at a solution
    I am not even understanding what the question is asking. All I know is the formula above. Can someone please help me out? Thank you.
     
  2. jcsd
  3. Aug 4, 2013 #2
    That formula is the answer unless you are given some particular equation for the curve.
     
  4. Aug 4, 2013 #3
    Oh, okay. So they are just asking for me to prove how I got to that using the x= r cos theta, y= r sin theta, and dy/dx= dy/dtheta / dx/dtheta formulas. Thank you!
     
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