1. The problem statement, all variables and given/known data A curve is given by the equation: y^3+1004=(e^x+1)^2 Find the slope of the tangent line at the point (0,-10). 2. Relevant equations 3. The attempt at a solution I took the derivative of ((e^x+1)^2-1004)^(1/3) and that is (2e^x(1+e^x))/(3((1+e^x)^2-1004)^(2/3)) but plugging in 0 for x does not give me the right answer.