- #1

utkarshakash

Gold Member

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## Homework Statement

Slope of the curve at the point x=0 of the function y=y(x) specified implicitly as [itex]\displaystyle \int_0^y e^{-t^2} dt + \int_0^x \cos t^2 dt = 0[/itex] is

## Homework Equations

## The Attempt at a Solution

Differentiating both sides wrt x

[itex]e^{-y^2} \frac{dy}{dx} + \cos x^2 = 0[/itex]

Now If I put x=0 above

[itex]\dfrac{dy}{dx} = \dfrac{-1}{e^{-y^2}} [/itex]

But I don't know the value of y when x = 0.