- #1
Jude075
- 20
- 0
Homework Statement
The function f(x)=5x2+3e2x is invertible. Give the slope of the normal line to the graph of f-1 at x=3
Homework Equations
(f-1)'(x)=1/f'(f-1(x))
The slope of the normal line × the slope of the tangent =-1
So basically I just need to find -f'(f-1(x)) at x=3
The Attempt at a Solution
Derivative of the original function is 10x+6e2x, but I cannot find f-1(x) as I am not able to inverse the function.
Thank you in advance