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Slow photodiode circuit

  1. Jul 1, 2008 #1
    Hi,

    I have a photodiode circuit (attached), where a photodiode is hooked up to a current to voltage opamp connected to a voltage divider. This circuit works as intended: when there is light, Vo ~ 3.3V, and when there is no light, Vo ~ 0.3V. However, when I measured the rise time of this circuit, I found out that it takes ~130ms to switch, which is much slower than I anticipated. The photodiode's spec says that its rise and fall time is 200us, and although I am not in the same operating condition, I expect the delay to be in the same order of magnitude, give or take. Therefore, if any1 has any idea on this, please let me know.

    Thanks.

    [opamp] http://focus.ti.com/lit/ds/symlink/opa657.pdf
    [photodiode] http://catalog.osram-os.com/catalog...=downloadFile&favOid=020000030000c448000100b6
     

    Attached Files:

  2. jcsd
  3. Jul 1, 2008 #2

    mgb_phys

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    Science Advisor
    Homework Helper

    Is that 1M for the feedback resistor - thats rather large.
    You haven't show the bias supply for the photodiode, are you just using the opamp input to bias it?
     
    Last edited: Jul 1, 2008
  4. Jul 1, 2008 #3
    Yes, that's 1M ohm. The reason why it's made large is because I wanted the output voltage BEFORE the voltage divider to be 5V (saturating the opamp) and then step it down to 3.3V AFTER the voltage divider. In fact, based on my calculation, the current generated by the photodiode is ~5uA. So to get 5V, I did, 5V = 5u*1M.

    It should be ok even if the Rf is large because it will simply saturate the opamp and get 5V as mentioned before.

    As for biasing, you are correct and I didn't bias the photodiode. I didn't realize you have to. I saw a proposed design from Sharp that used a simliar circuit so I thought it was fine. It's on page 3 Figure 6 of the link below

    http://vorlon.case.edu/~flm/eecs245/Datasheets/Sharp photodevices.pdf
     
  5. Jul 2, 2008 #4

    berkeman

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    Staff: Mentor

    To speed up your photodetector I --> V circuit, you need to reverse bias the diode (to lower its capacitance) and lower the feedback resistance (to speed up the associated RC time constant). No circuit with a 1Meg resistor in it is going to be fast. Don't forget to include the input capacitance of the opamp and the PCB parasitic trace capacitance in your RC calculations.
     
  6. Jul 3, 2008 #5
    Thanks for your suggestion. I will try them out.
     
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