Small limit problem

1. Nov 1, 2011

Student4

Stuck on really starting this one

relevant info: Same chapter as L’Hospital’s Rule.

Any ideas?

2. Nov 1, 2011

HallsofIvy

Staff Emeritus
Since this is in the same chapter as "L'Hopital's rule", it seems likely L'Hopital's rule will work!

To put it into that right form to use for L'Hopital's rule, take the logarithm of both sides:
$$ln(y)= ln((e^x+ sin(x))^{1/x})= \frac{ln(e^x+ sin(x)}{x}$$
Use L'Hopital's rule on that (both numerator and denominator go to 0), to find the limit of ln(y) then take the exponential to find the limit of y itself.

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