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Small question

  1. Apr 10, 2005 #1
    In an adiabatic process, I know that that dQ is zero. I am doing a problem with a cycle that has different types of processes, and when I get to the adiabatic leg, I am finding that the change in temperature is zero. Therefore, the work done and the change in internal energy also equal zero.

    Is this possible? Can an adiabatic process also have no change in temperature, therefore being isothermal?
     
  2. jcsd
  3. Apr 10, 2005 #2

    dextercioby

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    NO.


    Daniel.
     
  4. Apr 10, 2005 #3
    OK, so in the problem A->B is isobaric, B->C is adiabatic, C->D is isothermal, D->A is isochoric.

    Pa = 2atm, Va = 2 m^3, n = 1mole, Vb = 1/2Va, Pa = 2Pd

    I always end up with the temperatures of B and C both equaling 2.44x10^4 K. What am I doing wrong?
     
  5. Apr 10, 2005 #4
    I'm going to make a new post of this since it's really no longer a "small question."
     
  6. Apr 10, 2005 #5

    dextercioby

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    How come you end up with equal temp.?Post your work.

    Daniel.
     
  7. Apr 10, 2005 #6
    I posted my work in a new thread since it is not a small problem anymore.
     
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