Small question

1. Apr 10, 2005

flythisforme

In an adiabatic process, I know that that dQ is zero. I am doing a problem with a cycle that has different types of processes, and when I get to the adiabatic leg, I am finding that the change in temperature is zero. Therefore, the work done and the change in internal energy also equal zero.

Is this possible? Can an adiabatic process also have no change in temperature, therefore being isothermal?

2. Apr 10, 2005

dextercioby

NO.

Daniel.

3. Apr 10, 2005

flythisforme

OK, so in the problem A->B is isobaric, B->C is adiabatic, C->D is isothermal, D->A is isochoric.

Pa = 2atm, Va = 2 m^3, n = 1mole, Vb = 1/2Va, Pa = 2Pd

I always end up with the temperatures of B and C both equaling 2.44x10^4 K. What am I doing wrong?

4. Apr 10, 2005

flythisforme

I'm going to make a new post of this since it's really no longer a "small question."

5. Apr 10, 2005

dextercioby

How come you end up with equal temp.?Post your work.

Daniel.

6. Apr 10, 2005

flythisforme

I posted my work in a new thread since it is not a small problem anymore.