Does a baseball on a slinky have a smaller Beta, or balloon on a slinky? Explain.
Beta = b/sqrt(mk)
b: damping coefficient
k: spring constant
The Attempt at a Solution
I see that the spring constant k is the same for either the baseball or the balloon case, because the slinky acts like a spring, so k is the spring constant.
The damping coefficient is different for the 2 cases so is the mass.
Since the mass of the baseball is heavier, it is assumed that the baseball case has a smaller beta. But what about the damping coefficient, b? How will this affect the system? In which case is b larger? I am stuck here on how to relate b, and mass together to get the answer. Thanks for the help.