I'd like someone to confirm whether I am on the right track here. Most formulations of the twin paradox involve a sharp turn-around with infinite acceleration. I suppose that there is an SR-only description of a non-infinite acceleration - a kind of 'smooth' version of the twin paradox. But my maths are a bit rusty to work that out. I suppose that as a→∞, we will get the sharp twin paradox. If we invoke GR to let our travelling twin to declare himself at rest, then during the acceleration phase a uniform gravitational field fills the universe. During that phase our travelling twin experiences gravitation and his clock starts ticking more slowly than his far-away, free falling twin. The more far-away the stay-at-home twin is, the larger his gravitational potential is and the fastest his clock will tick with respect to the travelling twin. I feel confident that (if I were able to work out the math, which sadly I am not), the equations for the GR solution and the SR solution would yield the same result. Is my intuition correct?