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Smoothness of functions

  1. Aug 16, 2007 #1
    If [tex] f \cdot f [/tex] and [tex] f \cdot f \cdot f [/tex] is smooth, does it follow that [tex] f [/tex] is smooth?

    So does [tex] f \cdot f \in C^{\infty} \ \text{and} \ f \cdot f \cdot f \in C^{\infty} \Rightarrow f \in C^{\infty} [/tex]?

    Maybe we could generalize a bit more: Given that [tex] f^{n} , f^{n-1} \in C^{\infty} [/tex] does it follow that [tex] f \in C^{\infty} [/tex] (where [tex] f^n [/tex] is the function raised to some power [tex] n [/tex])?
    Last edited: Aug 16, 2007
  2. jcsd
  3. Aug 16, 2007 #2


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    Well, what does dividing tell you?
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