Hi guys. I am currently stuck on the classic snow plow problem. I have the following differential equation and initial conditions: @ 7am plow starts off to clear snow at a constant rate By 8am, plow has gone 4mi By 9am, plow has gone an additional 3mi Let t=0 when it started to snow, when did it start to snow. They gave the answer as 4:27am k(dx/dt)=1/t It wants me to find the constant k. Here is my work: ∫k dx= ∫dt/t kx +C = ln (t) At this point I am assuming that x is the independent variable and t is the dependent variable. e^(kx) +C = t Using the first initial condition of when it starts to snow of x(0)=0, I get the C is 0, therefore e^(kx) = t. Using the second initial condition @8, x(t+1)=4 e^(4k)= t+1. This is the point I get stuck. I cant seem to solve for k that has a real number. Any help would be appreciated.