Chemistry Problem: Solving with Molar Mass & Isotope Abundance

  • Thread starter cpatel23
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In summary, the problem involves finding the average molar mass for an element with two isotopes, X and Y, which have molar masses mx and my, and percentage abundances px and py. The equation for the average molar mass can be rearranged to solve for the relative abundance of the first isotope (x), assuming that the other isotope has a relative abundance of 1-x. By setting this equation equal to the given average molar mass, the value of x can be solved for.
  • #1
cpatel23
16
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Hello.
I am doing a chemistry problem but it is mainly mathematics

Here it is.

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A little info that is useful to this problem.

Molar mass is always an average, given by

Molar Mass = (mass of isotope1 * abundance of isotope 1) + (mass of isotope2 + abundance of isotope 2)

Masses of isotopes are always constant, they do not vary from place to place.

So how do I solve this?
 
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  • #2
While the molar masses do not change, the relative abundances can and do.

An element has isotopes X and Y which have molar masses mx and my with percentage abundances px and py ... rearrange those variables to give an equation for the average molar mass for the element.
 
  • #3
If we are to assume that the two isotopes given here are the only ones we need consider, then let "x" be the relative abundance of the first (U235) and then the relative abundance of the other (U238) is 1- x.

So we must have x(235.043924)+ (1- x)(238.050784)= 238.0375.

Solve that equation for x.
 

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