So embarrassed

1. Jan 24, 2006

Mozart

I don't remember how to do this x^(2/3)=4 solve for x Do you use logarithm or something?

2. Jan 24, 2006

matrixx333

I'm gonna try my best to explain. Whenever you have a fractional exponent, that is another way of talking about a radical...

The "3" in the denominator of the fraction is what "root" your radical will be:

Ex. square root of 2 = 21/2
cubed root of 2 = 21/3

now, the numerator is what power "X" is going to be:

Ex. square root of 21 = 21/2
cubed root of 22 = 22/3

That should hopefully get you started in the right direction.....

3. Jan 24, 2006

Mozart

After reading what you said I did the following.

wrote x^2 with the third root around it and made it equal 4.

I then took the square root of 4 to get rid of the square sign on x

I then cubed the 2 and got 8

After pugging the 8 into x^(2/3) I got 4

Please tell me I got the answer using a proper method and this isn't a cruel coincidence. Thanks by the way for the help!

Last edited: Jan 24, 2006
4. Jan 24, 2006

d_leet

sounds like you did it right.

5. Jan 24, 2006

Mozart

:surprised Thanks.

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