Is there any restriction to what type of acceleration should give Newton’s force - mass ratio? Should it be angular or linear or electric or whatever acceleration? The fact that the rigid bar on which the weights hold IS rigid means that the weights are rotating around the center of the lever and the angle of rotation for each weight is same. So, this force - mass ratio either could or must be expressed thru this angle, which enables that ratio to be equivalent with the angle. This also enables that ratio to be equivalent with the angular acceleration. Angular acceleration is not same with the linear one. If it was then it could be same also with electric acceleration that I define like some Coulombs over seconds squared.(adsbygoogle = window.adsbygoogle || []).push({});

So what type of acceleration gives Newton’s force - mass ratio?

After all I don’t think even angular acceleration is necessary to simulate the motion in one system. Look:

D_1 = (random, random, random) - nonzero distance of first weight.

F_1 = (random, random, random) - nonzero force of first weight.

D_2, F_2 - distance, force of second weight.

n = random (1, 100) - ratio of the distances.

A = random (0, 359) - the angle of rotation same for all.

[tex]make D_2 = \frac {-n}{|D_1|} D_1 [/tex]

[tex]make F_2 = \frac {-|D_1|}{|D_2|} F_1 [/tex]

[tex]for i = 1 and 2 make [/tex]

[tex]new (F_i) = cos(a) F_i - \frac {|F_i | sin(a)}{|D_i |} D_i [/tex]

[tex]new (D_i) = cos(a) D_i + \frac {|D_i | sin(a)}{|F_i |} F_i [/tex]

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# So Is It Angular Or Linear?

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