Danielle_riv
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Help Exam Tmr! 112 Physics *FORCES*
As you may have guessed from the title, I'm in a bit of a bind here. You see the website with the answers to the review questions I'm working on isn't working... and there's an exam tomorrow. Here's a few of the questions any help would be greatly appreciated.
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A 2.0kg fish is hooked on a line that rated to a max of 38 N. At one point, the fish pulls with 40 N of force (fish are weightless in water). What is the min acceration at which you must play out the line to avoid it from snapping?
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A 0.00021 kg spider is suspended from a thin strand of webbing. The greatest tension the strand can withstand without breaking is 0.002 N . What is the max acceleration with which the spider can safetly climb up the strand?
answers
ok so apparently i need to show my work so here goes:
for the fish question:
m= 2.0kg
Fmax=38N
Fxrt= 40N
a = ?
Fnet canot be more than 38N soo..
Fnet=ma
38=2.0a
a=19m/s2
that doesn't seem right to me... awfully fast to make up for 2 N wouldn't you think?
orr wait..
Fnet needs to be -2? so then..
-2=2.0a
a= -1m/s2
WHAT IS GOING ON HERE
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See the problem with the spider question is this: the Fg of the spider ends up being the same as the max Force... but where Fg is also the net force i should be able to use F=ma... plug that in and you end up with 9.52m/s2... which seems to completely contradict that fact.?.?.?.
I mean wouldn't the spider only be able to hang there with no acceration at all, unless that is he goes down instead of up... so maybe the answer is -9.52?
As you may have guessed from the title, I'm in a bit of a bind here. You see the website with the answers to the review questions I'm working on isn't working... and there's an exam tomorrow. Here's a few of the questions any help would be greatly appreciated.
--------
A 2.0kg fish is hooked on a line that rated to a max of 38 N. At one point, the fish pulls with 40 N of force (fish are weightless in water). What is the min acceration at which you must play out the line to avoid it from snapping?
---------
A 0.00021 kg spider is suspended from a thin strand of webbing. The greatest tension the strand can withstand without breaking is 0.002 N . What is the max acceleration with which the spider can safetly climb up the strand?
answers
ok so apparently i need to show my work so here goes:
for the fish question:
m= 2.0kg
Fmax=38N
Fxrt= 40N
a = ?
Fnet canot be more than 38N soo..
Fnet=ma
38=2.0a
a=19m/s2
that doesn't seem right to me... awfully fast to make up for 2 N wouldn't you think?
orr wait..
Fnet needs to be -2? so then..
-2=2.0a
a= -1m/s2
WHAT IS GOING ON HERE
----
See the problem with the spider question is this: the Fg of the spider ends up being the same as the max Force... but where Fg is also the net force i should be able to use F=ma... plug that in and you end up with 9.52m/s2... which seems to completely contradict that fact.?.?.?.
I mean wouldn't the spider only be able to hang there with no acceration at all, unless that is he goes down instead of up... so maybe the answer is -9.52?
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