An underwater observer is looking directly into the sun. His head is near, but below the surface, and he is not wearingsun glasses. Let Ls(x) be the solar radiance at the water surface, on the air side, when the sun is at a zenith angle x. What is the ratio of the solar radiance at the observer's eye to the solar radiance just above the water surface?
Here's where I'm having trouble. I'm not sure which equation is relevant. Is this simply a Fresnel transmission problem? I have equations for vertical and horizontal polarization
Rh = [sin2(xa - xw)]/[sin2(xa + xw)]
But I also have a solid angle formula for radiance at the air water boundary. It is labeled "From Snell's law and flux conservation" [tex]\Omega[/tex]a = n2 [cos xw/ cos x a ] [tex]\Omega[/tex] w
Where the [tex]\Omega[/tex]s are solid angle. The subscript a one is subtended by Ls in the accompanying diagram. And the subscript w by Ld (downwelling) so I'm not sure if this ratio would be what I need.
Thanks for your help!!!!