What is the Relationship Between Solar Wind and Kinetic Energy?

Click For Summary
SUMMARY

The solar wind carries kinetic energy away from the Sun at a calculable rate, which can be expressed in watts and as a fraction of the Sun's luminosity. The kinetic energy (KE) is determined using the formula KE=(1/2)mv^2, where 'm' represents the mass loss of the Sun. The mass loss can be calculated using the equation Msunloss=4πr²vρ, where 'r' is the radius of the Sun, 'v' is the velocity of the solar wind, and 'ρ' is the density of the solar wind. By substituting the appropriate values into these equations, one can derive the solar wind's kinetic energy output.

PREREQUISITES
  • Understanding of kinetic energy calculations using KE=(1/2)mv^2
  • Familiarity with solar wind properties, including velocity (v) and density (ρ)
  • Knowledge of the Sun's luminosity, specifically L=3.8*10^26 W
  • Basic grasp of astrophysical concepts related to mass loss and energy transfer
NEXT STEPS
  • Calculate the solar wind's kinetic energy using specific values for v and ρ
  • Explore the implications of solar wind on space weather and its effects on Earth
  • Research the relationship between solar wind and solar radiation pressure
  • Investigate the methods for measuring solar wind properties in astrophysics
USEFUL FOR

Astronomers, astrophysicists, students studying solar physics, and anyone interested in the dynamics of solar wind and its energy implications.

scotshocker
Messages
6
Reaction score
0

Homework Statement


At what rate does the solar wind carry kinetic energy away from the sun? Give your result first in watts, then as a fraction of the Sun's luminosity in photons, L=3.8*10^26 W


Homework Equations


KE=(1/2)mv^2
mass loss of sun- Msunloss=4πr2


The Attempt at a Solution


I think this is one of those problems that seems so simple I am second guessing myself. Is it really as simple as input the mass loss of the sun in for my m in the KE formula and then dividing it by a second to find the wattage and then converting into luminosity?
 
Physics news on Phys.org
If you know v and ρ: yes.
 

Similar threads

Replies
1
Views
2K
  • · Replies 79 ·
3
Replies
79
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
8K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 16 ·
Replies
16
Views
2K