1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Solid disk radius of gyration

  1. Dec 29, 2005 #1
    1. A solid disc of radius r, is rolling down a variable incline (a ramp). Show that the acceleration of the centre of mass, C is given by:

    a=g[ sinθ – F/Ncosθ ].
    I have done this as shown below.

    N is the normal reaction and F is friction.
    N = mgcosθ
    F = µN = µmgcosθ

    mgsinθ – F = ma
    mgsinθ – µmgcosθ = ma
    a = g[ sinθ – µcosθ ]

    but µ = F/N

    a=g[ sinθ – F/Ncosθ ]

    2. Determine an expression for the value of F/N where the only unknowns are the angle θ, the radius r and radius of gyration k.

    I have tried this question and can’t get the right answer and need some help please.
    I know
    T = Iα
    I = mk2 also for a solid disk I = 0.5mr2
    α = a/r
    Can anyone help with this question please?
  2. jcsd
  3. Dec 29, 2005 #2

    Doc Al

    User Avatar

    Staff: Mentor

    I find this question quite strange, since you should have no trouble finding the acceleration directly without using F/N. In any case, while your answer is correct, the method is not. You assume that friction equals µN, but this is not true in general. Remember this is static friction, so F is less than (or possibly equal to) µN.

    But you don't need to use µN at all; just stick to:
    N = mgcosθ
    mgsinθ – F = ma​
    and combine these two.

    Forget the radius of gyration; you don't need it. Combine the torque equation (T = Iα) with the force equation (mgsinθ – F = ma) and you can solve for the acceleration. And then find F/N.
  4. Dec 29, 2005 #3
    i have combined it but i get F/N = 1/3 TAN@
    But the question wants an expression with r and k in it also.
  5. Dec 29, 2005 #4

    Doc Al

    User Avatar

    Staff: Mentor

    If the disk is uniform, that's the correct answer. The only thing that I can think of is to pretend that you don't know if the disk is uniform or not. Then you can write the rotational inertia in terms of the radius of gyration and solve for the acceleration, then F/N. Then you'd have r and k in your answer.
  6. Jan 13, 2006 #5
    Why don't you try asking your lecturer, maybe she can help!!!
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Solid disk radius of gyration
  1. Radius of Gyration (Replies: 1)

  2. Radius of Gyration? (Replies: 2)