Hi,(adsbygoogle = window.adsbygoogle || []).push({});

I have the area [tex]D(x,y): \sqrt{x}e^{x^2}\leq y \leq 3,~~ 0\leq x \leq 1[/tex]

That is rotated about the x axis, and i need to calculate the area

[tex]\pi \int_0^1 3^2-y^2 = \pi \int_0^1 9-xe^{2x^2}[/tex]

[tex]\frac{-9\pi}{4}\cdot (e^{2x^2}-1)\bigg|_0^1[/tex]

But this is all wrong, why?

**Physics Forums - The Fusion of Science and Community**

# Solids of revolution

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Solids of revolution

Loading...

**Physics Forums - The Fusion of Science and Community**