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Solubility in base

  • Thread starter HyeLim
  • Start date
1
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In my lab, I'm trying to identify an unknown compound. So I did a solubility test of the unknown into 5% NaOH. According to the manual it said that if it appears insoluble,take the supernatant out and add 5% HCl until neutral. If percipitate or turbidity results, it means the unknown is an acid.
So far I thought this:
HA (unknown) + OH- <-> H20 + A-
I'm assuming the conjugate base was in the supernatant, but I'm not sure.
A- + HCl <-> Cl- + HA
I'm not sure where the percipitate or turbidity is from. Please help me!
 

Answers and Replies

symbolipoint
Homework Helper
Education Advisor
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In the first part, the organic acid present dissolved (why you obtained the very soluble A anion). Later, you added H+ which recombined with the A- giving you back the fairly insoluble organic acid again, the HA. The HA causes this turbidity or precipitation.
 

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