Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Biology and Chemistry Homework Help
Solubility Product, finding molar concentration
Reply to thread
Message
[QUOTE="Ace., post: 4618926, member: 449486"] [h2]Homework Statement [/h2] If the 2.0 x 10[SUP]-5[/SUP] mol of Cu(IO[SUB]3[/SUB])[SUB]2[/SUB] can dissolve in 2 L of NaIO[SUB]3[/SUB], find the molar concentration of the NaIO[SUB]3[/SUB] solution. Ksp = 1.4 x 10[SUP]-7[/SUP] for Cu(IO[SUB]3[/SUB])[SUB]2[/SUB].[h2]Homework Equations[/h2] [h2]The Attempt at a Solution[/h2] Let y = [IO3-(aq)] present in the solution from NaIO3 Cu(IO[SUB]3[/SUB])[SUB]2[/SUB](s) ↔ Cu[SUP]2+[/SUP](aq) + 2IO[SUB]3[/SUB][SUP]-[/SUP](aq) I [itex]\:\:\:\:[/itex] excess [itex]\:\:\:\:[/itex] 0 [itex]\:\:\:\:\:\:\:\:\:\:\:\:\:[/itex] y C [itex]\:\:\:\:[/itex] -x[itex]\:\:\:\:\:\:\:\:\:[/itex] +1x10-5 [itex]\:\:\:\:[/itex] +2x10-5 E [itex]\:\:\:\:[/itex]excess [itex]\:\:\:\:[/itex] 1x10-5 [itex]\:\:\:\:[/itex] y + 2x10-5 Ksp = [Cu[SUP]2+[/SUP]][IO[SUB]3[/SUB][SUP]1-[/SUP]][SUP]2[/SUP] 1.4 * 10[SUP]-7[/SUP] = [1.0 * 10[SUP]-5[/SUP]][y + 2.0 * 10[SUP]-5[/SUP]] y = 0.118M That is the correct answer but I am wondering why you don't divide by 2, since isn't 2IO[SUB]3[/SUB][SUP]-[/SUP] in 2:1 ratio with NaIO[SUB]3[/SUB]? I'm just totally confused when to use the ratios and when not to (like in this case). [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Biology and Chemistry Homework Help
Solubility Product, finding molar concentration
Back
Top