1. The problem statement, all variables and given/known data What is the solubility of Mg(OH)2 in a solution buffered at pH 8.80. 2. Relevant equations 3. The attempt at a solution The answer is .45 M or 26 g/L but I can't get that for some reason. I can find the concentration of hydroxide [OH-] = 6.3 x 10-6 Mg(OH)2 -> Mg+2 + 2OH- ................0+x,....6.3x10-6 + 2x 1.8x10-11 = x(6.3x10-6 + 2x)^2 x = 1.65 x 10-4 M (neglecting the 6.3 x10-6) I've also tried solving the cubic with similar results. Does anyone where I went wrong?