Calculate Mass of Magnesium Sulphate in 500 mL Stock MnSo4

[veena]

Homework Statement

Solid Magnesium sulphate exists only as a mono hydrate . Calculate the mass of this solute in 500 mL of the stock MnSo4 used in this experiment.

Homework Equations

Plz help

The Attempt at a Solution

 

[symbolipoint]

Density is mass divided by volume. How was the magnesium sulfate solution prepared? How much mass of the magnesium sulfate monohydrate was added to how much mass of water? Was measurement of the volume of the resultant solution needed?

 

[Blueshift5]

To calculate the mass of magnesium sulphate in 500 mL of the stock solution, we first need to determine the concentration of the stock solution. This can be done by using the formula:

C = (n/V)

Where C is the concentration in moles per liter (mol/L), n is the number of moles of solute, and V is the volume of the solution in liters.

We can rearrange this formula to solve for n:

n = C x V

Next, we need to convert the given volume of the solution (500 mL) into liters by dividing it by 1000:

V = 500 mL / 1000 = 0.5 L

Now, we need to determine the concentration of the stock solution. This information may be given in the experiment or can be calculated using the mass of the solute and the volume of the solution. For example, if the stock solution was prepared by dissolving 10 grams of magnesium sulphate in 500 mL of water, the concentration would be:

C = (10 g / 120 g/mol) / 0.5 L = 0.167 mol/L

Using this concentration, we can now calculate the number of moles of magnesium sulphate in 500 mL of the stock solution:

n = (0.167 mol/L) x (0.5 L) = 0.0835 mol

Finally, to calculate the mass of magnesium sulphate, we need to use its molar mass, which is 120 g/mol. We can use the formula:

m = n x M

Where m is the mass in grams, n is the number of moles, and M is the molar mass in grams per mole.

Plugging in the values, we get:

m = (0.0835 mol) x (120 g/mol) = 10.02 g

Therefore, the mass of magnesium sulphate in 500 mL of the stock solution is approximately 10.02 grams.