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Homework Statement
X^2 + 1 = 0
Homework Equations
find the solution
The Attempt at a Solution
As simple as this:
what is the solution to x^2 +1 = 0
.... my question, why am I wrong in thinking x^2 = -1 as a possible solution?
Oh I see.... Well, a solution to x^2 could be [tex]\pm 1[/tex]. So what is the solution, I am a bit confused. Would it beX^2 = -1 is not a solution for "what is x", which is what is being asked for, it is a solution to "what is X^2"
(-1/2)² = 1/4, so that's not a solution to X² + 1 =0Oh I see.... Well, a solution to x^2 could be [tex]\pm 1[/tex]. So what is the solution, I am a bit confused. Would it be
x = -1/2
No, it's not. You have already said that x^2= -1, not [itex]\pm 1[/itex]. Now you need to get x itself, not x^2. You need to "undo" the square- what's the opposite of squaring?Oh I see.... Well, a solution to x^2 could be [tex]\pm 1[/tex].
You seem to be confused about what "solution to an equation" means. What level mathematics are you taking? Where did you get this problem? Have you studied complex numbers.So what is the solution, I am a bit confused. Would it be
x = -1/2
So the solution is(-1/2)² = 1/4, so that's not a solution to X² + 1 =0
You are right in re-arranging your equation as X² = -1
now take the square root of both sides.
Bravo.So the solution is
[tex]x = \sqrt{-1}[/tex]
[tex]x=\pm\sqrt{-1}[/tex]So the solution is
[tex]x = \sqrt{-1}[/tex]
To the OP: you know the symbol we use for [itex]\sqrt{-1}[/itex], right?[tex]x=\pm\sqrt{-1}[/tex]
Yes, it's the imaginary number. :)
In other words, what symbol do we use to represent ##\sqrt{-1}##?Which imaginary number?
Righti = sqrt{-1}