(x^2)(y^3) + x(1 + y^2)y' = 0(adsbygoogle = window.adsbygoogle || []).push({});

the integrating factor to make the above equation exact is (1)/(xy^3)

i have worked this equation out and have c = .5x^2 as the solution; however, the textbook says the solution is c = x^2 - y^(-2) + 2lnlyl

apparently they got this solution because h'(y) = y^(-3) + y(-1)

i found h'(y) to be equal to zero.

some sort of feedback would be greatly appreciated.

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# Solution to the exact differential equation

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