- #1

danago

Gold Member

- 1,122

- 4

[tex]

\left| {2x + 1} \right| \ge \left| {x - 3} \right|

[/tex]

Now, i must solve for x. I could easily do it by graphing it on my calculator, and get an answer of [tex]x \le - 4,x \ge \frac{2}{3}[/tex].

How can i do it algebraically?

Thanks in advance,

Dan.

\left| {2x + 1} \right| \ge \left| {x - 3} \right|

[/tex]

Now, i must solve for x. I could easily do it by graphing it on my calculator, and get an answer of [tex]x \le - 4,x \ge \frac{2}{3}[/tex].

How can i do it algebraically?

Thanks in advance,

Dan.

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