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Homework Help: Solve a simple problem in MATLAB

  1. Oct 30, 2014 #1
    1. The problem statement, all variables and given/known data
    ow to create a function to determine the area of a polynomial that has N vertexes in MATLAB?

    2. Relevant equations
    p = input('Introduce the number of vertexes of the polynomial:')

    The polynomial can be devided by N-2 triangles and the area of each triangle is given by A=(1/2)*det(B) where B=[x1 x2 x3 .... xn; y1 y2 y3 .... yn; 1 1 1 1 1 ...... 1(last row is filled with n ones)]

    3. The attempt at a solution
    p = input('Introduce the number of vertexes of the polynomial:')
    if n<3:
    (...) - I tried 'if cicles' and sums but I don't know know how to ask for all x and y of the polynomial vertexes (because the size of the matrix varies with the number of vertexes of the polynomial).

    Would apreciate any kind of help :D
  2. jcsd
  3. Oct 30, 2014 #2
    You have to ask all the coordinates of the vertexes
  4. Oct 30, 2014 #3
    Already solved it:

    function p = area_polinomio(N)
    area = 0;
    A = [0,0,0;0,0,0;0,0,0];
    if N < 3
    warning('pontos insuficientes')
    a = [input('introduza a abcissa do primeiro ponto: '); input('\n introduza a ordenada do primeiro ponto: '); 1];
    for i = 1 : N-1
    b = [input('\n introduza a abcissa do ponto seguinte: '); input('\n introduza a ordenada do ponto seguinte: '); 1];
    if i == 1
    A = [a, b];
    if i == 2
    A = [A, b];
    area = area + (1/2)*det(A);
    if i > 2
    A = A(:,[1:1,3,3:2,2,4:end]);
    A = A(1:3,1:2);
    A = [A, b];
    area = area + (1/2)*det(A);

    i = i+1;

  5. Oct 31, 2014 #4


    Staff: Mentor

    The word you're searching for is polygon, a two-dimensional figure with three or more straight sides that intersect at the vertices of the polygon. Triangles, rectangles, and hexagons are examples of polygons.

    A polynomial is an expression made up of sums of integer powers of the variable. For example, f(x) = 2x + 3, g(x) = x2 - 3x + 2, and h(x) = x4 - 1 are polynomial functions of degree 1, 2, and 4 respectively.
  6. Oct 31, 2014 #5
    LOOOL. That made me laugh xD
    A silly misake made by me. Acually when I was solving this I named the function area_polynomial and not area_polygon until it was time to run it, then I changed the name. Was completely focused on the exercise xD
  7. Oct 31, 2014 #6


    Staff: Mentor

    Are you from Portugal or Brazil? I'm just curious...
  8. Oct 31, 2014 #7
    Portugal :)
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