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Solve algebraically

  1. Jan 21, 2009 #1
    im having a problem solving this problem algebraically please help thanks

    e^x - 15e^-x = 2
  2. jcsd
  3. Jan 21, 2009 #2
    put e^x = y. And then solve for y
  4. Jan 21, 2009 #3


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    Homework Helper

    Remember the rule: [tex]a.b^{-c}=\frac{a}{b^c}[/tex]

    You will have a quadratic in [tex]e^x[/tex]
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