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Solve differential equation

4xdy - ydx = (x^2)dy

The attempt at a solution

(4x - x^2)dy = ydx

(1/y)dy = (1/(4x - x^2))dx

Integrating both sides:

For integrating 1/(4x - x^2) i completed the square for the denominator part and got 4-(x-2)^2 then used substitution; let (x-2) = 2sint

lny = sin^-1((x-2)/2) + lnA

But the answer wrong for some reason unknown to me.

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# Solve differential equation

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