- #1

usfz28

- 19

- 0

Given the velocity of the electron, I can found out the kinetic energy of the electron 1/2MV^2=K.E.

With the K.E. I can then use f=((work funct)+(K.E.))/(H) to find the Freq. () With that I can then find λ=(C)/(F). to find λ the wavelength.

Then I finally can find the initial energy state by using:

N(initial)=Sq Root(((k(e)^2)/2(Aof zero)hc)-1/λ+n(final)^2))

Does that sound about right? Sorry about all the parenthesis