# Solve F'(x)

1. Feb 19, 2007

### MattsAli1108

1. The problem statement, all variables and given/known data
F(x)= square root of x

what would F'(x)=?
(F prime of x)

2. Relevant equations

F(x)= 3x^2
F'(x)=6x

F(x)= x^3
F'(x)=3x^2

3. The attempt at a solution

no clue. If the variable is a square root, it wouldn't have an exponent, right?
confused.

Last edited: Feb 19, 2007
2. Feb 19, 2007

### cristo

Staff Emeritus
The general equation you're after is $$\frac{d}{dx}(x^n)=nx^{n-1}$$
Have you not come across fractional powers? i.e. the nth root of x is denoted x1/n?

3. Feb 19, 2007

### MattsAli1108

I have, just failed to make the connection. Calculus is not my strong point. Thank you very much for your help.