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Solve F'(x)

  1. Feb 19, 2007 #1
    1. The problem statement, all variables and given/known data
    F(x)= square root of x

    what would F'(x)=?
    (F prime of x)


    2. Relevant equations

    F(x)= 3x^2
    F'(x)=6x

    F(x)= x^3
    F'(x)=3x^2

    3. The attempt at a solution

    no clue. If the variable is a square root, it wouldn't have an exponent, right?
    confused.
     
    Last edited: Feb 19, 2007
  2. jcsd
  3. Feb 19, 2007 #2

    cristo

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    Staff Emeritus
    Science Advisor

    The general equation you're after is [tex]\frac{d}{dx}(x^n)=nx^{n-1}[/tex]
    Have you not come across fractional powers? i.e. the nth root of x is denoted x1/n?
     
  4. Feb 19, 2007 #3
    I have, just failed to make the connection. Calculus is not my strong point. Thank you very much for your help.
     
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