How do I solve for F in
Feb 28, 2020 #1 alg 6 0 How do I solve for F in View attachment 9570 Attachments Screen Shot 2020-02-28 at 9.16.34 AM.png 865 bytes · Views: 39
Feb 28, 2020 #2 topsquark Science Advisor Insights Author Gold Member MHB 1,835 801 frctl said: How do I solve for F in Hint: Multiply both sides of the equation by 5/9. -Dan
Feb 28, 2020 #4 skeeter 1,104 1 frctl said: Is the following correct? 9/5C = 9/5F - 9/5(1/32) C = F - 1/32 F = C + 1/32 not quite ... $C = \dfrac{9}{5}(F-32)$ as suggested by topsquark ... ${\color{red}\dfrac{5}{9}} \cdot C = {\color{red}\dfrac{5}{9}} \cdot \dfrac{9}{5}(F-32)$ $\dfrac{5}{9} \cdot C = \cancel{\dfrac{5}{9}} \cdot \cancel{\dfrac{9}{5}} ( F - 32)$ (note that any number times its reciprocal equals 1) $\dfrac{5}{9} \cdot C = F - 32$ can you finish ?
frctl said: Is the following correct? 9/5C = 9/5F - 9/5(1/32) C = F - 1/32 F = C + 1/32 not quite ... $C = \dfrac{9}{5}(F-32)$ as suggested by topsquark ... ${\color{red}\dfrac{5}{9}} \cdot C = {\color{red}\dfrac{5}{9}} \cdot \dfrac{9}{5}(F-32)$ $\dfrac{5}{9} \cdot C = \cancel{\dfrac{5}{9}} \cdot \cancel{\dfrac{9}{5}} ( F - 32)$ (note that any number times its reciprocal equals 1) $\dfrac{5}{9} \cdot C = F - 32$ can you finish ?
Feb 28, 2020 #6 skeeter 1,104 1 frctl said: F = 9/5C + 32 correction ... $F=\dfrac{5}{9} \cdot C + 32$
