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Forums
Mathematics
General Math
Help Needed: Solving x and Simplifying Equations
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[QUOTE="skeeter, post: 6785004, member: 1088"] frequency is the reciprocal of period (time to complete one cycle of AC) $T = \dfrac{1}{50} = 0.02 \text{ sec } = 20 \text{ milliseconds}$ current flow (with no lag) as a function of time in milliseconds ... $A = 0.5 \sin\left(\dfrac{\pi}{10} \cdot t \right)$ For that period, the sinusoidal graph of current would peak at $\dfrac{T}{4} = 5 \text{ milliseconds}$ Due to the lag, there is a 1 millisecond horizontal shift in the graph ... [B]In future, please start a new problem with a new thread.[/B] [/QUOTE]
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Forums
Mathematics
General Math
Help Needed: Solving x and Simplifying Equations
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