Solve for X

1. Oct 10, 2006

thomasrules

Solve for X:

$$3(2)^x = 4(^x^+^1)$$

I did:

$$xlog3(2)=(x+1)log4$$

Last edited: Oct 10, 2006
2. Oct 10, 2006

Hootenanny

Staff Emeritus
You do know that your calculator can only handle logarithms to the bases e or 10?

3. Oct 10, 2006

thomasrules

yea so u gotta find x

4. Oct 10, 2006

arildno

Why do you believe:
$$\log(3*2^{x})=x\log(3*2)$$????

5. Oct 10, 2006

thomasrules

the way i wrote it, I used the logarithm law...

6. Oct 10, 2006

arildno

No you didn't. You used your own recently invented logarithm "law"

Tell me how you misapplied the correct logarithm laws.

7. Oct 10, 2006

thomasrules

if thats not the way then how? its because of that stupid 3 in front

8. Oct 10, 2006

arildno

Correct!
It's because of that stupid 3 in front!

Now, if you have two numbers a,b, what can you say about:
$$\log(a*b)=??$$

9. Oct 10, 2006

thomasrules

god damnit got the wrong answer again...

I thought u meant... $$loga+logb$$

10. Oct 10, 2006

arildno

Correct! So, if $a=3, b=2^{x}$,
what do you get on the right-hand side of your equation when you take the log?

11. Oct 10, 2006

thomasrules

Nevermind I Got It!!! Thanks You...i"m A Genious!

12. Oct 10, 2006

thomasrules

haha court <3

13. Oct 10, 2006

arildno

There WAS a post by courtigrad, I KNEW IT! He deleted it way too fast for me.

I will not rest until I find out..

14. Oct 10, 2006

it was just a test... to see what words are blocked out.

15. Oct 10, 2006

arildno

*****, ****, **** and so on?

16. Oct 10, 2006

yes. just an experiment

17. Oct 10, 2006

arildno

What were the words, did they get blocked?

18. Oct 10, 2006

arildno

Definite need of filter improvement.