- #1

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## Homework Statement

The √ sign extends over x+3 only. Solve for x.

√(x+3) + 3 = 9

## The Attempt at a Solution

subtract 3 from each side

√(x+3) = 6

√(33 + 3) = 6

√36 = 6

x = 33

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- Thread starter LLS
- Start date

- #1

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The √ sign extends over x+3 only. Solve for x.

√(x+3) + 3 = 9

subtract 3 from each side

√(x+3) = 6

√(33 + 3) = 6

√36 = 6

x = 33

- #2

Defennder

Homework Helper

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- #3

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Thank you.

I've been told that I am an odd person, LOL!!

:)

Have a safe weekend.

I've been told that I am an odd person, LOL!!

:)

Have a safe weekend.

- #4

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[tex]\sqrt{x + 3}[/tex] = 6

Until here, everything is fine but then you have to square both sides and guarantee that the expression that is under the root is not negative (which now can be excluded because we clearly see that 6 is positive, otherwise if we had a variable there, for example [tex]\sqrt{x + 3}[/tex] = x + 2 can be solved by solving a system - ([tex]\sqrt{x + 3}[/tex])^2 = (x + 2)^2; x + 3 [tex]\geq0[/tex])

So follows:

x + 3 = 36

x = 33

I hope you can understand my explanation.

EDIT: Too late

- #5

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I understand, thank you.

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