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lim x->0 3sin4x/sin3x i do not know how to reduce the sin4x? and do i even use the property where lim x->0 sinx/x =1?
no, there's an identity that's probably on the inside cover of your textbook. it goes something like sin(a+b) = cos(a)sin(b) + cos(b)sin(a). i can't remember how that formula goes but it's something like that.zell_D said:ok thx another REAL DUMB question on my part lol havent done math for so long, when i make sin4x into sin2(2x) and then into 2sin2xcos2x, do i use distributive property with the 3?
The suggestions so far would work, but are not the best way.zell_D said:lim x->0 3sin4x/sin3x i do not know how to reduce the sin4x? and do i even use the property where lim x->0 sinx/x =1?
Pretty clever.lurflurf said:The suggestions so far would work, but are not the best way.
[tex]\lim_{x\rightarrow 0}\frac{3\sin(4x)}{\sin(3x)}=\lim_{x\rightarrow 0}4\frac{\sin(4x)}{4x} \ \frac{3x}{\sin(3x)}[/tex]
Both of those limits are equal to the know limit for sin(x)/x
That would mean for any point on the graph (c,f(c)) -1<c<1zell_D said:o wow that was much ezier thx alot guys, sorry for all the bothering =/
and lasty, i am suppose to state whether this statment is true or false with this graph, obviously i cant draw the graph on here but would one of you tell me what does:
lim x-> c f(x) exists at every c in (-1, 1) mean?