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Solve the trig

  • Thread starter hayowazzup
  • Start date
  • #1
64
0

Homework Statement


1 = 121 sinθ *cosθ + 592.9 (cos²θ)


Homework Equations





The Attempt at a Solution



1= 60.5 * 2 *sin θ *cosθ + 592.9 (cos²θ)
1= 60.5 sin 2θ + 592.9 (cos²θ)
1-60.5 sin 2θ / cos θ cos θ= 592.9

am i doing it rite? i don't know what to do
 

Answers and Replies

  • #2
761
13
Use [tex] sin^2 + cos^2 =1 [/tex]
 
  • #3
64
0
but i don't know how to get rid of sin θ *cosθ
 
  • #4
Dick
Science Advisor
Homework Helper
26,258
618
You wrote sin(theta)*cos(theta) in terms of sin(2*theta). Write cos(theta)^2 in terms of cos(2*theta).
 

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