# Solve the trig

1. ### hayowazzup

64
1. The problem statement, all variables and given/known data
1 = 121 sinθ *cosθ + 592.9 (cos²θ)

2. Relevant equations

3. The attempt at a solution

1= 60.5 * 2 *sin θ *cosθ + 592.9 (cos²θ)
1= 60.5 sin 2θ + 592.9 (cos²θ)
1-60.5 sin 2θ / cos θ cos θ= 592.9

am i doing it rite? i don't know what to do

2. ### dirk_mec1

705
Use $$sin^2 + cos^2 =1$$

3. ### hayowazzup

64
but i don't know how to get rid of sin θ *cosθ

4. ### Dick

25,887
You wrote sin(theta)*cos(theta) in terms of sin(2*theta). Write cos(theta)^2 in terms of cos(2*theta).