Solve the trig

  1. 1. The problem statement, all variables and given/known data
    1 = 121 sinθ *cosθ + 592.9 (cos²θ)


    2. Relevant equations



    3. The attempt at a solution

    1= 60.5 * 2 *sin θ *cosθ + 592.9 (cos²θ)
    1= 60.5 sin 2θ + 592.9 (cos²θ)
    1-60.5 sin 2θ / cos θ cos θ= 592.9

    am i doing it rite? i don't know what to do
     
  2. jcsd
  3. Use [tex] sin^2 + cos^2 =1 [/tex]
     
  4. but i don't know how to get rid of sin θ *cosθ
     
  5. Dick

    Dick 25,887
    Science Advisor
    Homework Helper

    You wrote sin(theta)*cos(theta) in terms of sin(2*theta). Write cos(theta)^2 in terms of cos(2*theta).
     
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