- #1
Mica
- 32
- 0
Hi,
Can someone give me a hint for solving this equation?
V0 - dQ(t)/dt * R(t) - Q(t)/C(t) = 0
Thanks,
Mica
Can someone give me a hint for solving this equation?
V0 - dQ(t)/dt * R(t) - Q(t)/C(t) = 0
Thanks,
Mica
The purpose of solving this equation is to determine the voltage (V0) at a given time interval by taking into account the change in charge (dQ/dt) and the resistance (R) and capacitance (C) of the system.
This equation is derived from Ohm's law (V = IR) and the formula for capacitance (C = Q/V). By substituting V=IR into the formula for capacitance, we can solve for V0 by considering the change in charge (dQ/dt) over time.
V0 is measured in volts (V), dQ/dt is measured in amperes per second (A/s), R is measured in ohms (Ω), and C is measured in farads (F).
Yes, this equation assumes that the system is in a steady state, meaning that the voltage, current, and charge are not changing over time. It also assumes that the resistance and capacitance values are constant throughout the system.
This equation is commonly used in circuit analysis and design to determine the voltage at a specific point in time. It is also used in fields such as electronics, electrical engineering, and physics to model and analyze systems with capacitors and resistors.