- #1

- 160

- 8

Solve the following equation with algebraic fractions

x/5 - (2x+4)/3 = 1

- Thread starter tomtomtom1
- Start date

- #1

- 160

- 8

Solve the following equation with algebraic fractions

x/5 - (2x+4)/3 = 1

- #2

rock.freak667

Homework Helper

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Expand out -(2x+4)/3 and then use your normal rules of algebra. Are you able to expand -(2x+4)/3 ?

- #3

- 160

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is it 2x/3 + 4/3

- #4

rock.freak667

Homework Helper

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Right so (2x+5)/3 = 2x/3 + 4/3. If you put this into your equation you will have:is it 2x/3 + 4/3

x/5 - (2x/3 +4/3) = 1

Can you simplify the left side of this equation using your standard algebra rules?

- #5

- 160

- 8

3x/15 - 10x/15 + 4/3

-7x/15 + 4/3 = 1

-7x/15 + 4/3 = 1

- #6

rock.freak667

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For -(2x/3 + 4/3) you are essentially multiplying each term in the bracket by -1. So you should not have +4/3. What should you have instead? After you do that, make -7x/15 the subject of the formula.3x/15 - 10x/15+ 4/3

-7x/15 + 4/3 = 1

- #7

- 160

- 8

3x/15 - 10x/15 - 4/3 = 1

-7x/15 - 4/3 = 1

-7x/15 = 1 + 4/3

-7x = (1+4/3)*15

-7x = 15+(60/3)

-7x = 35

x = 35/-7

x = -5

Thanks

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