- #1

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I need to find dz/dx in terms of x and y, if:

Z = x^2y - 2xy^2 + y - 8 and y = 2x^2 +3/x!

tried solving it a few times, but its a difficult one! any help and working out would be great!

- Thread starter Becky
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- #1

- 2

- 0

I need to find dz/dx in terms of x and y, if:

Z = x^2y - 2xy^2 + y - 8 and y = 2x^2 +3/x!

tried solving it a few times, but its a difficult one! any help and working out would be great!

- #2

Hurkyl

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We'd be better able to help if you show us what you've done.

- #3

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Ok dz/dx

x = 2y - 4y +y

y = 4x + 3

dont think that is right!

x = 2y - 4y +y

y = 4x + 3

dont think that is right!

- #4

quasar987

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- #5

HallsofIvy

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- #6

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i think i can help,dz/dx=x^2y[dy/dx(log[x^2])+2y/x]-2y^2-4xydy/dx+dy/dx

where dy/dx=4x - {3/x!}[1/x+1/x-1+1/x-2+1/x-3.......]

- #7

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hallsofivy ur step was wrong since y is a function of x cant differentiate like that

check ur solution one more time,ur step will be right if the question reads x^2 times y ,but if it is x raised to the power of 2y then mine is correct.also i hope the 6 in the function 4xy6y' was a typing mistake cos if it is not then ur answer is wrong.

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