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[SOLVED] speed of electrons
In the Bohr model of the hydrogen atom, an electron circles a proton at a radius of 5.3e-11 m. How fast must the electron be moving if the centripetal acceleration is to be supplied by Coulombic attraction?
L=n(h/2pi) where h is Plancks constant and n is an integer
L=rmv
n(h/2pi)=rmv
v=n(h/2pi)/(rm)
v= n(6.63e-34/2pi)/(5.3e-4)(9.11e-31)
v= 0.218n m/s
Now that velocity seems way to small for a speed of an electron...
Any help is appreciated! Thanks!
Homework Statement
In the Bohr model of the hydrogen atom, an electron circles a proton at a radius of 5.3e-11 m. How fast must the electron be moving if the centripetal acceleration is to be supplied by Coulombic attraction?
Homework Equations
L=n(h/2pi) where h is Plancks constant and n is an integer
L=rmv
The Attempt at a Solution
n(h/2pi)=rmv
v=n(h/2pi)/(rm)
v= n(6.63e-34/2pi)/(5.3e-4)(9.11e-31)
v= 0.218n m/s
Now that velocity seems way to small for a speed of an electron...
Any help is appreciated! Thanks!