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Phoenixtears
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A proton is fired horizontally with a speed of 1.1 106 m/s through the parallel-plate capacitor shown in Figure P34.37. The capacitor's electric field is = (1.3 105 V/m, down) and the distance between the plates is 31 millimeter.
(Image Attached)
The proton entered the capacitor gap 18.6 milli-meters above the lower plate. Where doe the proton strike the lower plate?
Measured in meters from the front edge of the lower plate.
Kinematics Equations
There were other questions on this problem that I already solved for. So here are other things that I know:
The magnitude of the acceleration= 1.245E13 m/s/s
Voltage difference= 4030 V
Now I've set up a kinematics table (seperate for horizontal and verticle):
Known for horizontal: Initial V= 1.1E6; A= 1.245E13
Uknown: distance, final velocity, time
Known for verticle: x= .0186 meters; Initial v= 0
Uknown: final velocity, acceleration, time
Any suggestions? I've no idea where to go from here.
Thanks in advance!
~Phoenix
Homework Statement
A proton is fired horizontally with a speed of 1.1 106 m/s through the parallel-plate capacitor shown in Figure P34.37. The capacitor's electric field is = (1.3 105 V/m, down) and the distance between the plates is 31 millimeter.
(Image Attached)
The proton entered the capacitor gap 18.6 milli-meters above the lower plate. Where doe the proton strike the lower plate?
Measured in meters from the front edge of the lower plate.
Homework Equations
Kinematics Equations
The Attempt at a Solution
There were other questions on this problem that I already solved for. So here are other things that I know:
The magnitude of the acceleration= 1.245E13 m/s/s
Voltage difference= 4030 V
Now I've set up a kinematics table (seperate for horizontal and verticle):
Known for horizontal: Initial V= 1.1E6; A= 1.245E13
Uknown: distance, final velocity, time
Known for verticle: x= .0186 meters; Initial v= 0
Uknown: final velocity, acceleration, time
Any suggestions? I've no idea where to go from here.
Thanks in advance!
~Phoenix
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