- #1

vDrag0n

- 3

- 0

## Homework Statement

int (1/(4-r^2)^0.5) dr dx, r=0 to 2sinx, x=0 to 2pi

## Homework Equations

How to continue the integral of x

## The Attempt at a Solution

I'm stuck at

int(arcsin(sinx)) dx, x=0 to 2pi

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- Thread starter vDrag0n
- Start date

- #1

vDrag0n

- 3

- 0

int (1/(4-r^2)^0.5) dr dx, r=0 to 2sinx, x=0 to 2pi

How to continue the integral of x

I'm stuck at

int(arcsin(sinx)) dx, x=0 to 2pi

- #2

Mark44

Mentor

- 36,311

- 8,281

This is your iterated integral:## Homework Statement

int (1/(4-r^2)^0.5) dr dx, r=0 to 2sinx, x=0 to 2pi

## Homework Equations

How to continue the integral of x

## The Attempt at a Solution

I'm stuck at

int(arcsin(sinx)) dx, x=0 to 2pi

[tex]\int_{x = 0}^{2\pi}\int_{r = 0}^{2 sin(x)}\frac{1}{\sqrt{4 - r^2}}dr~dx[/tex]

I'm pretty sure you evaluated the inner integral incorrectly, most likely because you have a mistake in your trig substitution.

For this integral

[tex]\int_0^{2 sin(x)}\frac{1}{\sqrt{4 - r^2}}dr[/tex]

I get 2 sin(x)

That makes the outer integral pretty simple.

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